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PhysicsMediumMCQ2018 · 08 Apr

Q25.Unpolarized light of intensity I passes through an ideal polariser A . Another identical polariser B is placed behind A . The intensity of light beyond B is found to be I . Now another identical polariser C is placed 2 between A and B. The intensity beyond B is now found to be I . The angle between polariser A and C is 8 (1) 60° (2) 0° (3) 30° (4) 45°

What This Question Tests

This problem applies Malus's Law to calculate the intensity of light after passing through multiple polarizers at different relative angles.

Concepts Tested

Malus's LawIntensity of polarized lightPolarization by successive polarizersUnpolarized light passing through polarizer

Formulas Used

I = I₀ cos²θ

I_polarized = I_unpolarized / 2

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