Q47.The Tyndall effect is observed only when the following conditions are satisfied, i The diameter of the dispersed particles is much smaller than the wavelength of the light used. ii The diameter of the dispersed particle is not much smaller than the wavelength of the light used. iii The refractive indices of the dispersed phase and dispersion medium are almost similar in magnitude. iv The refractive indices of the dispersed phase and dispersion medium differ greatly in magnitude. (1) ii and iv (2) i and iii (3) ii and iii (4) i and iv
What This Question Tests
This question tests the factual knowledge about the specific conditions required for the observation of the Tyndall effect in colloidal solutions.
Concepts Tested
📚 NCERT Sections This Tests
1.1 — Define The Term Solution. How Many Types Of Solutions Are Formed? Write Briefly
Chemistry Class 11 · Chapter 1
1.1 Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
9.17 — (A) Sin I¢C = 1.44/1.68 Which Gives I¢C = 59°. Total Internal Reflection
Physics Class 12 · Chapter 9
9.17 (a) sin i¢c = 1.44/1.68 which gives i¢c = 59°. Total internal reflection takes place when i > 59° or when r < rmax = 31°. Now, (sin i /sin r max max ) = 1.68 , which gives imax ~ 60°. Thus, all incident rays of angles in the range 0 < i < 60° will suffer total internal reflections in the pipe. (If the length of the pipe is finite, which it is in practice, there will be a lower limit on i determined by the ratio of the diameter to the length of the pipe.) (b) If there is no outer coating, i¢c = sin–1(1/1.68) = 36.5°. Now, i = 90° will have r = 36.5° and i¢ = 53.5° which is greater than i¢c. Thus, all incident rays (in the range 53.5° < i < 90°) will suffer total internal reflections.
1.23 — Suggest The Most Important Type Of Intermolecular Attractive Interaction In
Chemistry Class 11 · Chapter 1
1.23 Suggest the most important type of intermolecular attractive interaction in the following pairs. (i) n-hexane and n-octane (ii) I2 and CCl4 (iii) NaClO4 and water (iv) methanol and acetone (v) acetonitrile (CH3CN) and acetone (C3H6O). 1.24 Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain. Cyclohexane, KCl, CH3OH, CH3CN.
📋 Question Details
- Chapter
- Surface Chemistry
- Topic
- Colloids
- Year
- 2017
- Shift
- 02 Apr
- Q Number
- Q47
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 5: Surface Chemistry
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