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MathsMediumMCQ2023 ยท 30 Jan Shift 1

Q68.If ๐‘ƒ( โ„Ž, ๐‘˜) be point on the parabola ๐‘ฅ= 4๐‘ฆ2, which is nearest to the point ๐‘„( 0, 33 ) , then the distance of ๐‘ƒ from the directrix of the parabola ๐‘ฆ2 = 4 ( ๐‘ฅ+ ๐‘ฆ) is equal to: (1) 2 (2) 4 (3) 8 (4) 6

What This Question Tests

The problem tests finding the point on a parabola closest to a given external point using calculus (differentiation) and then calculating the distance of that point from the directrix of a different parabola.

Concepts Tested

Distance formulaMinimization using derivativesEquation of directrix of a parabola

Formulas Used

Distance = sqrt((x2-x1)^2 + (y2-y1)^2)

dD/dx = 0 for extremum

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