Q81.Let x, y be positive real numbers and m, n positive integers. The maximum value of the expression xmyn is : (1+x2 m)(1+y2n) (1) 1 (2) 1 2 (3) 1 (4) m+n 4 6mn
What This Question Tests
This question tests the ability to find the maximum value of an expression involving multiple positive real numbers by strategically applying the AM-GM inequality.
Concepts Tested
Formulas Used
AM >= GM (a+b)/2 >= sqrt(ab)
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
9.18 — For Fixed Distance S Between Object And Screen, The Lens Equation
Physics Class 12 · Chapter 9
9.18 For fixed distance s between object and screen, the lens equation does not give a real solution for u or v if f is greater than s/4. Therefore, fmax = 0.75 m.
📋 Question Details
- Chapter
- Applications of Derivatives
- Topic
- Maxima and Minima
- Year
- 2019
- Shift
- 11 Jan Shift 2
- Q Number
- Q81
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences & Series
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