Q22.The magnitude of the magnetic field at the centre of an equilateral triangular loop of side 1 m which is carrying a current of 10 A is: [Take μ0 = 4π × 10-7 N A-2 ] (1) 3 μT (2) 1 μT (3) 18 μT (4) 9 μT
What This Question Tests
This question tests the application of the formula for the magnetic field due to a finite straight current-carrying wire to find the net magnetic field at the center of an equilateral triangular loop.
Concepts Tested
Formulas Used
B = (μ₀I / 4πd) * (sinθ₁ + sinθ₂)
d = L / (2√3) (for equilateral triangle center)
📚 NCERT Sections This Tests
4.4 — A Horizontal Overhead Power Line Carries A Current Of 90 A In East To
Physics Class 11 · Chapter 4
4.4 A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?
4.9 — A Square Coil Of Side 10 Cm Consists Of 20 Turns And Carries A Current
Physics Class 11 · Chapter 4
4.9 A square coil of side 10 cm consists of 20 turns and carries a current of 12 A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30º with the direction of a uniform horizontal magnetic field of magnitude 0.80 T. What is the magnitude of torque experienced by the coil?
4.6 — A 3.0 Cm Wire Carrying A Current Of 10 A Is Placed Inside A Solenoid
Physics Class 11 · Chapter 4
4.6 A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
📋 Question Details
- Chapter
- Magnetic Effects of Current
- Topic
- Magnetic field due to current loops
- Year
- 2019
- Shift
- 10 Apr Shift 2
- Q Number
- Q22
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 4: Magnetic Effects of Current
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