Q31.Which transition in the hydrogen spectrum would have the same wavelength as the Balmer type transition from n = 4 to n = 2 of He+spectrum (1) n = 2 to n = 1 (2) n = 1 to n = 3 (3) n = 1 to n = 2 (4) n = 3 to n = 4
What This Question Tests
This question requires using the Rydberg formula to calculate wavelengths for transitions in hydrogen and He+ and finding matching wavelengths.
Concepts Tested
Formulas Used
1/λ = RZ² (1/n₁² - 1/n₂²)
📚 NCERT Sections This Tests
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
Physics Class 12 · Chapter 12
12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Bohr's model, Wavelength of spectral lines
- Year
- 2023
- Shift
- 31 Jan Shift 1
- Q Number
- Q31
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 2: Atomic Structure
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