Q58.The resistance of conductivity cell with cell constant 1. 14 cm−1 , containing 0. 001M KCl at 298 K is 1500Ω . The molar conductivity of 0. 001M KCl solution at 298 K in S cm2 mol−1 is (Integer answer)
What This Question Tests
This question involves calculating the equilibrium constant Kp for the decomposition of a solid, given its degree of decomposition and initial conditions.
Concepts Tested
Formulas Used
Kp = P(NH3) * P(H2S)
PV = nRT
📚 NCERT Sections This Tests
2.9 — The Resistance Of A Conductivity Cell Containing 0.001M Kcl Solution At 298
Chemistry Class 11 · Chapter 2
2.9 The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 W. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10–3 S cm–1. 59 Electrochemistry Reprint 2025-26
2.8 — The Conductivity Of 0.20 M Solution Of Kcl At 298 K Is 0.0248 S Cm–1. Calculate
Chemistry Class 11 · Chapter 2
2.8 The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm–1. Calculate its molar conductivity.
2.7 — Define Conductivity And Molar Conductivity For The Solution Of An Electrolyte.
Chemistry Class 11 · Chapter 2
2.7 Define conductivity and molar conductivity for the solution of an electrolyte. Discuss their variation with concentration.
📋 Question Details
- Chapter
- Chemical Equilibrium
- Topic
- Equilibrium constant Kp
- Year
- 2021
- Shift
- 27 Aug Shift 2
- Q Number
- Q58
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 7: Equilibrium
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