Q67.The number of solutions of the equation, sin−1 x = 2 tan−1 x (in principal values) is : (1) 1 (2) 4 (3) 2 (4) 3
What This Question Tests
The question tests the ability to solve an equation involving inverse trigonometric functions by converting them to a common form and checking for valid solutions within their principal value domains.
Concepts Tested
Formulas Used
2tan⁻¹x = tan⁻¹(2x/(1-x²))
sin⁻¹x = tan⁻¹(x/√(1-x²))
📚 NCERT Sections This Tests
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
1.1 — Define The Term Solution. How Many Types Of Solutions Are Formed? Write Briefly
Chemistry Class 11 · Chapter 1
1.1 Define the term solution. How many types of solutions are formed? Write briefly about each type with an example.
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
📋 Question Details
- Chapter
- Inverse Trigonometric Functions
- Topic
- Solving inverse trigonometric equations
- Year
- 2013
- Shift
- 22 Apr Online
- Q Number
- Q67
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 2: Inverse Trigonometric Functions
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