Q17.If Mo is the mass of isotope 125 B, MP and Mn are the masses of proton and neutron, then nuclear binding energy of isotope is : (1) (Mo −5Mp)C 2 (2) (5Mp + 7Mn −Mo)C 2 (3) (M0 −12Mn)C 2 (4) (Mo −5Mp −7Mn)C 2
What This Question Tests
This question directly tests the formula for nuclear binding energy, which is calculated from the mass defect and Einstein's mass-energy equivalence relation.
Concepts Tested
Formulas Used
ΔE_b = (Z M_p + N M_n - M_nucleus)c²
📚 NCERT Sections This Tests
13.2 — Obtain The Binding Energy Of The Nuclei 5626Fe And 20983 Bi In Units Of
Physics Class 12 · Chapter 13
13.2 Obtain the binding energy of the nuclei 5626Fe and 20983 Bi in units of MeV from the following data: m ( 5626Fe ) = 55.934939 u m ( 20983 Bi ) = 208.980388 u
13.5 — The Q Value Of A Nuclear Reaction A + B ® C + D Is Defined By
Physics Class 12 · Chapter 13
13.5 The Q value of a nuclear reaction A + b ® C + d is defined by Q = [ mA + mb – mC – md]c2 where the masses refer to the respective nuclei. Determine from the given data the Q-value of the following reactions and state whether the reactions are exothermic or endothermic. (i) 11 H+13 H →12 H+12 H (ii) 126 C+126 C →1020 Ne+ 24 He Atomic masses are given to be m ( 12 H ) = 2.014102 u m ( 13 H) = 3.016049 u m ( 126 C ) = 12.000000 u m ( 1020 Ne ) = 19.992439 u
13.3 — A Given Coin Has A Mass Of 3.0 G. Calculate The Nuclear Energy That
Physics Class 12 · Chapter 13
13.3 A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of 6329Cu atoms (of mass 62.92960 u).
📋 Question Details
- Chapter
- Nuclei
- Topic
- Nuclear binding energy
- Year
- 2024
- Shift
- 08 Apr Shift 2
- Q Number
- Q17
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 13: Nuclei
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