Q16.If the distance between object and its two times magnified virtual image produced by a curved mirror is 15 cm , the focal length of the mirror must be : (1) 15 cm (2) โ12 cm (3) โ10 cm (4) 103 cm
What This Question Tests
This question requires applying the mirror formula and magnification formula, along with proper sign conventions, to determine the focal length of a curved mirror that forms a magnified virtual image.
Concepts Tested
Formulas Used
1/f = 1/v + 1/u
m = -v/u
m = 2 (virtual image)
๐ NCERT Sections This Tests
9.15 โ Apply Mirror Equation And The Condition:
Physics Class 12 ยท Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
9.2 โ A 4.5 Cm Needle Is Placed 12 Cm Away From A Convex Mirror Of Focal
Physics Class 12 ยท Chapter 9
9.2 A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror.
9.19 โ A Screen Is Placed 90Cm From An Object. The Image Of The Object On
Physics Class 12 ยท Chapter 9
9.19 A screen is placed 90cm from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by 20cm. Determine the focal length of the lens.
๐ Question Details
- Chapter
- Ray Optics
- Topic
- Curved Mirrors, Magnification
- Year
- 2024
- Shift
- 29 Jan Shift 2
- Q Number
- Q16
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 9: Ray Optics and Optical Instruments
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