Q24.A soap bubble is blown to a diameter of 7 cm.36960erg of work is done in blowing it further. If surface tension of soap solution is 40dyne/cm then the new radius is______ cm Take (π = 227 )
What This Question Tests
This question requires calculating the work done to increase the surface area of a soap bubble, considering it has two surfaces, to find the new radius.
Concepts Tested
Formulas Used
W = T * ΔA
ΔA = 2 * 4π(R₂² - R₁²)
📚 NCERT Sections This Tests
2.4 — A Spherical Conductor Of Radius 12 Cm Has A Charge Of 1.6 × 10–7C
Physics Class 11 · Chapter 2
2.4 A spherical conductor of radius 12 cm has a charge of 1.6 × 10–7C distributed uniformly on its surface. What is the electric field (a) inside the sphere (b) just outside the sphere (c) at a point 18 cm from the centre of the sphere?
2.2 — A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 · Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
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Physics Class 12 · Chapter 12
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📋 Question Details
- Chapter
- Properties of Matter
- Topic
- Surface tension and surface energy
- Year
- 2024
- Shift
- 04 Apr Shift 1
- Q Number
- Q24
- Type
- Numerical
- NCERT Ref
- Class 11 Physics Ch 10: Properties of Matter
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