Q61.The equation √3x2 + x + 5 = x −3, where x is real, has (1) no solution (2) exactly four solutions (3) exactly one solution (4) exactly two solutions JEE Main 2014 (19 Apr Online) JEE Main Previous Year Paper
What This Question Tests
This question requires solving a radical equation by squaring both sides, but critically emphasizes the need to define the domain for the variable and check for extraneous solutions after solving the resulting quadratic equation.
Concepts Tested
Formulas Used
√(f(x)) = g(x) => f(x) = (g(x))^2 AND g(x) >= 0
📚 NCERT Sections This Tests
14.2 — Which Of The Statements Given In Exercise 14.1 Is True For P-Type
Physics Class 12 · Chapter 14
14.2 Which of the statements given in Exercise 14.1 is true for p-type semiconductos.
9.15 — Apply Mirror Equation And The Condition:
Physics Class 12 · Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
9.18 — For Fixed Distance S Between Object And Screen, The Lens Equation
Physics Class 12 · Chapter 9
9.18 For fixed distance s between object and screen, the lens equation does not give a real solution for u or v if f is greater than s/4. Therefore, fmax = 0.75 m.
📋 Question Details
- Chapter
- Quadratic Equations
- Topic
- Solving radical equations
- Year
- 2014
- Shift
- 19 Apr Online
- Q Number
- Q61
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 5: Quadratic Equations
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