Q85.The area (in square units) bounded by the curves y=√x, 2y −x + 3 = 0 , X -axis and lying in the first quadrant is (1) 18 sq. units (2) 274 sq. units (3) 9 sq. units (4) 36 sq. units
What This Question Tests
This question tests the knowledge of a key property of definite integrals (King's Rule) and its application in evaluating a specific integral, requiring careful calculation to determine the truthfulness of the first statement.
Concepts Tested
Formulas Used
∫[a to b] f(x)dx = ∫[a to b] f(a+b-x)dx
📚 NCERT Sections This Tests
1.18 — A Point Charge Of 2.0 Mc Is At The Centre Of A Cubic Gaussian
Physics Class 11 · Chapter 1
1.18 A point charge of 2.0 mC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?
5.2 — Lists The Kinetic Energies For Various X I
Physics Class 11 · Chapter 5
5.2 lists the kinetic energies for various x i objects. where the summation is from the initial position ⊳ xi to the final position xf. Example 5.4 In a ballistics demonstration a police officer fires a bullet of mass 50.0 g If the displacements are allowed to approach with speed 200 m s-1 (see Table 5.2) on soft zero, then the number of terms in the sum plywood of thickness 2.00 cm. The bullet increases without limit, but the sum approaches emerges with only 10% of its initial kinetic a definite value equal to the area under the curve energy. What is the emergent speed of the in Fig. 5.3(b). Then the work done is bullet ? xf W = lim F (x )∆xAnswer The initial kinetic energy of the bullet ∆ x → 0 ∑ x i is mv2/2 = 1000 J. It has a final kinetic energy xfof 0.1×1000 = 100 J. If vf is the emergent speed x ) d x (5.7)of the bullet, = ∫F ( i 1 2 x mv f = 100 J where ‘lim’ stands for the limit of the sum when 2 ∆x tends to zero. Thus, for a varying force 2 × 100 J the work done can be expressed as a definite v f = 0. 05 kg integral of force over displacement (see also Appendix 3.1). = 63.2 m s–1 The speed is reduced by approximately 68% (not 90%). ⊳
1.14 — Consider A Uniform Electric Field E = 3 × 103 Î N/C. (A) What Is The
Physics Class 11 · Chapter 1
1.14 Consider a uniform electric field E = 3 × 103 î N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
📋 Question Details
- Chapter
- Definite Integration & Area
- Topic
- Properties of definite integrals
- Year
- 2013
- Shift
- 07 Apr
- Q Number
- Q85
- Type
- Assertion Reasoning
- NCERT Ref
- Class 12 Mathematics Ch 7: Integrals
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