Q58.Spin only magnetic moment of [MnBr6]4− is _____ B.M. (round off to the closest integer)
What This Question Tests
This question requires calculating the spin-only magnetic moment for a coordination complex by determining the number of unpaired electrons using the electronic configuration of the central metal ion and considering the ligand field.
Concepts Tested
Formulas Used
μ = √n(n+2) BM
📚 NCERT Sections This Tests
5.23 — Give The Oxidation State, D Orbital Occupation And Coordination Number Of
Chemistry Class 11 · Chapter 5
5.23 Give the oxidation state, d orbital occupation and coordination number of the central metal ion in the following complexes: (i) K3[Co(C2O4)3] (iii) (NH4)2[CoF4] (ii) cis-[CrCl2(en)2]Cl (iv) [Mn(H2O)6]SO4
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.18 — What Is Crystal Field Splitting Energy? How Does The Magnitude Of Do Decide
Chemistry Class 11 · Chapter 5
5.18 What is crystal field splitting energy? How does the magnitude of Do decide the actual configuration of d orbitals in a coordination entity?
📋 Question Details
- Chapter
- Coordination Compounds
- Topic
- Magnetic properties of coordination compounds
- Year
- 2022
- Shift
- 29 Jun Shift 2
- Q Number
- Q58
- Type
- Numerical
- NCERT Ref
- Class 12 Chemistry Ch 9: Coordination Compounds
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