Q40.Benzene on nitration gives nitrobenzene in presence of HNO3 and H2 SO4 mixture, where: (1) both H2 SO4 and HNO3 act as a bases (2) HNO3 acts as an acid and H2 SO4 acts as a base (3) both H2 SO4 and HNO3 act as an acids (4) HNO3 acts as a base and H2 SO4 acts as an acid
What This Question Tests
This question tests the understanding of the role of sulfuric acid and nitric acid in the nitration of benzene, specifically how they generate the electrophile NO2+.
Concepts Tested
📚 NCERT Sections This Tests
7.16 — Explain How Does The –Oh Group Attached To A Carbon Of Benzene Ring
Chemistry Class 12 · Chapter 7
7.16 Explain how does the –OH group attached to a carbon of benzene ring activate it towards electrophilic substitution?
9.8 — Accomplish The Following Conversions:
Chemistry Class 12 · Chapter 9
9.8 Accomplish the following conversions: (i) Nitrobenzene to benzoic acid (ii) Benzene to m-bromophenol (iii) Benzoic acid to aniline (iv) Aniline to 2,4,6-tribromofluorobenzene (v) Benzyl chloride to 2-phenylethanamine (vi) Chlorobenzene to p-chloroaniline (vii) Aniline to p-bromoaniline (viii) Benzamide to toluene (ix) Aniline to benzyl alcohol.
7.8 — Ortho And Para Nitrophenols Are More Acidic Than Phenol. Draw The
Chemistry Class 12 · Chapter 7
7.8 Ortho and para nitrophenols are more acidic than phenol. Draw the resonance structures of the corresponding phenoxide ions.
📋 Question Details
- Chapter
- Hydrocarbons
- Topic
- Electrophilic Aromatic Substitution (Nitration)
- Year
- 2021
- Shift
- 20 Jul Shift 2
- Q Number
- Q40
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 13: Hydrocarbons
More from this Chapter
Q62. The IUPAC name of is (1) 1, 1−diethyl −2, 2−dimethylpentane (2) 4, 4−dimethyl −5, 5−diethylpentane (3) 5, 5−diethyl −4, 4−diemthylpentane (4) 3−ethyl −4, 4−dimethylheptane
Q63.The reaction of toluene with Cl2 in presence of FeCl3 gives predominantly (1) benzoyl chloride (2) benzyl chloride (3) o−and p−chlorotoluene (4) m−chlorotoluene
Q76.Which of the following reactions will yield 2, 2−dibromopropane? (1) CH3 −C ≡CH + 2HBr ⟶ (2) CH3CH ≡CHBr + HBr ⟶ (3) CH ≡CH + 2HBr ⟶ (4) CH3 −CH = CH2 + HBr ⟶
Q79.The compound formed as a result of oxidation of ethyl benzene by KMnO4 is (1) benzophenone (2) acetophenone (3) benzoic acid (4) benzyl alcohol