Q10.The charge on capacitor of capacitance 15μF in the figure given below is (1) 60 μC (2) 130 μC (3) 260 μC (4) 585 μC
What This Question Tests
This question tests the ability to analyze a DC circuit containing capacitors in steady state, using Kirchhoff's laws to find the potential difference across a capacitor and then its charge.
Concepts Tested
Formulas Used
Q = CV
Kirchhoff's Voltage Law
📚 NCERT Sections This Tests
2.7 — Three Capacitors Of Capacitances 2 Pf, 3 Pf And 4 Pf Are Connected
Physics Class 11 · Chapter 2
2.7 Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
8.1 — Figure 8.5 Shows A Capacitor Made Of Two Circular Plates Each Of
Physics Class 11 · Chapter 8
8.1 Figure 8.5 shows a capacitor made of two circular plates each of radius 12 cm, and separated by 5.0 cm. The capacitor is being charged by an external source (not shown in the figure). The charging current is constant and equal to 0.15A. (a) Calculate the capacitance and the rate of change of potential difference between the plates. (b) Obtain the displacement current across the plates. (c) Is Kirchhoff’s first rule (junction rule) valid at each plate of the capacitor? Explain. FIGURE 8.5
2.6 — Three Capacitors Each Of Capacitance 9 Pf Are Connected In Series.
Physics Class 11 · Chapter 2
2.6 Three capacitors each of capacitance 9 pF are connected in series. (a) What is the total capacitance of the combination? (b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
📋 Question Details
- Chapter
- Current Electricity
- Topic
- Capacitors in DC circuits
- Year
- 2022
- Shift
- 26 Jun Shift 2
- Q Number
- Q10
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 2: Electrostatic Potential and Capacitance, Class 12 Physics Ch 3: Current Electricity
More from this Chapter
Q50.By increasing the temperature, the specific resistance of a conductor and a semiconductor (1) increases for both (2) decreases for both (3) increases, decreases (4) decreases, increases
Q51. If in the circuit, power dissipation is 150 W, then R is (1) 2Ω (2) 6Ω (3) 5Ω (4) 4Ω JEE Main 2002 JEE Main Previous Year Paper
Q28.If θi , is the inversion temperature, θn is the neutral temperature, θc is the temperature of the cold junction, then (1) θi + θc = θn (2) θi −θc = 2θn (3) θi+θc 2 = θn (4) θc −θi = 2θn
Q47.If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a (1) low resistance in parallel (2) high resistance in parallel (3) high resistance in series (4) low resistance in series