Q61. Ksp for Cr(OH)3 is 1.6 × 10−30 . What is the molar solubility of this salt in water? (1) 1.8×10−30 (2) 5√1.8 × 10−30 27 × 10−30 (3) 4√1.6×10−3027 (4) 2√1.6
What This Question Tests
This question is a straightforward application of the solubility product concept to calculate the molar solubility of a sparingly soluble salt from its Ksp value.
Concepts Tested
Formulas Used
Ksp = [Cr³⁺][OH⁻]³
S = molar solubility
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📋 Question Details
- Chapter
- Ionic Equilibrium
- Topic
- Solubility product
- Year
- 2025
- Shift
- 24 Jan Shift 1
- Q Number
- Q61
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 7: Ionic Equilibrium
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