Q59.The product (C) in the following sequence of reactions has ______ π bonds.
What This Question Tests
This question tests the knowledge of different reagents for the reduction of alkynes to alkenes (trans vs. cis) and subsequent reactions, specifically bromination of an alkene and counting pi bonds in the final product.
Concepts Tested
📚 NCERT Sections This Tests
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
6.21 — Primary Alkyl Halide C4H9Br (A) Reacted With Alcoholic Koh To Give Compound (B).
Chemistry Class 12 · Chapter 6
6.21 Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.
📋 Question Details
- Chapter
- Hydrocarbons
- Topic
- Reactions of Alkenes and Alkynes
- Year
- 2024
- Shift
- 05 Apr Shift 2
- Q Number
- Q59
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 13: Hydrocarbons
More from this Chapter
Q62. The IUPAC name of is (1) 1, 1−diethyl −2, 2−dimethylpentane (2) 4, 4−dimethyl −5, 5−diethylpentane (3) 5, 5−diethyl −4, 4−diemthylpentane (4) 3−ethyl −4, 4−dimethylheptane
Q63.The reaction of toluene with Cl2 in presence of FeCl3 gives predominantly (1) benzoyl chloride (2) benzyl chloride (3) o−and p−chlorotoluene (4) m−chlorotoluene
Q76.Which of the following reactions will yield 2, 2−dibromopropane? (1) CH3 −C ≡CH + 2HBr ⟶ (2) CH3CH ≡CHBr + HBr ⟶ (3) CH ≡CH + 2HBr ⟶ (4) CH3 −CH = CH2 + HBr ⟶
Q79.The compound formed as a result of oxidation of ethyl benzene by KMnO4 is (1) benzophenone (2) acetophenone (3) benzoic acid (4) benzyl alcohol