Q60.Alternating current can not be measured by D.C. ammeter because (1) A.C. cannot pass through D.C. (2) A.C. changes direction (3) average value of current for complete cycle is (4) D.C. ammeter will get damaged. zero
What This Question Tests
This conceptual question asks why a DC ammeter cannot measure AC, testing the knowledge of the average value of alternating current over a full cycle.
Concepts Tested
๐ NCERT Sections This Tests
7.3 โ Representation Of Ac Current And Voltage
Physics Class 11 ยท Chapter 7
7.3 REPRESENTATION OF AC CURRENT AND VOLTAGE BY ROTATING VECTORS โ PHASORS In the previous section, we learnt that the current through a resistor is in phase with the ac voltage. But this is not so in the case of an inductor, a capacitor or a combination of these circuit elements. In order to show phase relationship between voltage and current in an ac circuit, we use the notion of phasors. The analysis of an ac circuit is facilitated by the use of a phasor diagram. A phasor* is a vector which rotates about the origin with angular speed w, as shown in Fig. 7.4. The vertical components of phasors V and I represent the sinusoidally varying quantities v and i. The magnitudes of phasors V and I represent the amplitudes or the peak values vm and im of these oscillating quantities. Figure 7.4(a) shows the FIGURE 7.4 (a) A phasor diagram for the voltage and current phasors and their circuit in Fig 7.1. (b) Graph of v and i versus wt.relationship at time t1 for the case of an ac source connected to a resistor i.e., corresponding to the circuit shown in Fig. 7.1. The projection of voltage and current phasors on vertical axis, i.e., vm sinwt and im sinwt, respectively represent the value of voltage and current at that instant. As they rotate with frequency w, curves in Fig. 7.4(b) are generated. From Fig. 7.4(a) we see that phasors V and I for the case of a resistor are in the same direction. This is so for all times. This means that the phase angle between the voltage and the current is zero.
8.2 โ A Parallel Plate Capacitor (Fig. 8.6) Made Of Circular Plates Each Of Radius
Physics Class 11 ยท Chapter 8
8.2 A parallel plate capacitor (Fig. 8.6) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to 213 a 230 V ac supply with a (angular) frequency of 300 rad sโ1. Reprint 2025-26 Physics (a) What is the rms value of the conduction current? (b) Is the conduction current equal to the displacement current? (c) Determine the amplitude of B at a point 3.0 cm from the axis between the plates. FIGURE 8.6 8.3 What physical quantity is the same for X-rays of wavelength 10โ10 m, red light of wavelength 6800 ร and radiowaves of wavelength 500m? 8.4 A plane electromagnetic wave travels in vacuum along z-direction. What can you say about the directions of its electric and magnetic field vectors? If the frequency of the wave is 30 MHz, what is its wavelength? 8.5 A radio can tune in to any station in the 7.5 MHz to 12 MHz band. What is the corresponding wavelength band? 8.6 A charged particle oscillates about its mean equilibrium position with a frequency of 10 9 Hz. What is the frequency of the electromagnetic waves produced by the oscillator? 8.7 The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave? 8.8 Suppose that the electric field amplitude of an electromagnetic wave is E0 = 120 N/C and that its frequency is n = 50.0 MHz. (a) Determine, B0,w, k, and l. (b) Find expressions for E and B. 8.9 The terminology of different parts of the electromagnetic spectrum is given in the text. Use the formula E = hn (for energy of a quantum of radiation: photon) and obtain the photon energy in units of eV for different parts of the electromagnetic spectrum. In what way are the different scales of photon energies that you obtain related to the sources of electromagnetic radiation? 8.10 In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 ร 1010 Hz and amplitude 48 V mโ1. (a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field? (c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 ร 108 m sโ1.] Reprint 2025-26
4.10 โ Two Moving Coil Meters, M1 And M2 Have The Following Particulars:
Physics Class 11 ยท Chapter 4
4.10 Two moving coil meters, M1 and M2 have the following particulars: R1 = 10 โฆ, N1 = 30, A1 = 3.6 ร 10โ3 m2, B1 = 0.25 T R2 = 14 โฆ, N2 = 42, A2 = 1.8 ร 10โ3 m2, B2 = 0.50 T (The spring constants are identical for the two meters). Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.
๐ Question Details
- Chapter
- AC Circuits
- Topic
- Measurement of AC
- Year
- 2004
- Shift
- Unknown
- Q Number
- Q60
- Type
- Conceptual
- NCERT Ref
- Class 12 Physics Ch 7: AC Circuits
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