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ChemistryMediumNumerical2023 · 25 Jan Shift 1

Q44.Consider the cell Pt(s)|H2( s)(latm)|H+(aq, [H+] = 1) Fe3+(aq), Fe2+(aq) ∣Pt (s) 1 H2°= 0 V, T = 298 K Given: EFe3+ / Fe2+°= 0. 771 V and EH+/ 2 If the potential of the cell is 0. 712 V the ratio of concentration of Fe2+ to Fe3+ is (Nearest integer)

What This Question Tests

This question tests the application of the Nernst equation to calculate the ratio of concentrations of Fe2+ to Fe3+ given the cell potential and standard electrode potentials.

Concepts Tested

Standard electrode potentialNernst equationCell potential calculation

Formulas Used

E_cell = E°_cell - (0.0591/n) log Q

E°_cell = E°_cathode - E°_anode

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