Q29.An object ' O' is placed at a distance of 100 cm in front of a concave mirror of radius of curvature 200 cm as shown in the figure. The object starts moving towards the mirror at a speed 2 cm sโ1 . The position of the image from the mirror after 10 s will be at _____ cm.
What This Question Tests
This question requires applying the mirror formula to find the image position, and then using the concept of image velocity relative to object velocity to find the new image position after a given time.
Concepts Tested
Formulas Used
1/f = 1/v + 1/u
f = R/2
dv/dt = -(v/u)ยฒ du/dt
๐ NCERT Sections This Tests
9.1 โ A Small Candle, 2.5 Cm In Size Is Placed At 27 Cm In Front Of A Concave
Physics Class 12 ยท Chapter 9
9.1 A small candle, 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image. If the candle is moved closer to the mirror, how would the screen have to be moved?
9.2 โ A 4.5 Cm Needle Is Placed 12 Cm Away From A Convex Mirror Of Focal
Physics Class 12 ยท Chapter 9
9.2 A 4.5 cm needle is placed 12 cm away from a convex mirror of focal length 15 cm. Give the location of the image and the magnification. Describe what happens as the needle is moved farther from the mirror.
9.15 โ Apply Mirror Equation And The Condition:
Physics Class 12 ยท Chapter 9
9.15 Apply mirror equation and the condition: (a) f < 0 (concave mirror); u < 0 (object on left) (b) f > 0; u < 0 (c) f > 0 (convex mirror) and u < 0 (d) f < 0 (concave mirror); f < u < 0 to deduce the desired result.
๐ Question Details
- Chapter
- Ray Optics
- Topic
- Mirror formula and velocity of image
- Year
- 2022
- Shift
- 28 Jul Shift 2
- Q Number
- Q29
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 9: Ray Optics and Optical Instruments
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