Q15.The equivalent capacitance between A and B in the circuit given below is: (1) 4.9μF (2) 3.6μF (3) 5.4μF (4) 2.4μF
What This Question Tests
This question tests the ability to calculate the equivalent capacitance of a circuit containing capacitors connected in series and parallel combinations.
Concepts Tested
Formulas Used
C_eq = C₁ + C₂ (parallel)
1/C_eq = 1/C₁ + 1/C₂ (series)
📚 NCERT Sections This Tests
2.7 — Three Capacitors Of Capacitances 2 Pf, 3 Pf And 4 Pf Are Connected
Physics Class 11 · Chapter 2
2.7 Three capacitors of capacitances 2 pF, 3 pF and 4 pF are connected in parallel. (a) What is the total capacitance of the combination? (b) Determine the charge on each capacitor if the combination is connected to a 100 V supply.
2.6 — Three Capacitors Each Of Capacitance 9 Pf Are Connected In Series.
Physics Class 11 · Chapter 2
2.6 Three capacitors each of capacitance 9 pF are connected in series. (a) What is the total capacitance of the combination? (b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?
2.5 — A Parallel Plate Capacitor With Air Between The Plates Has A
Physics Class 11 · Chapter 2
2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10–12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
📋 Question Details
- Chapter
- Electrostatics
- Topic
- Capacitors in series and parallel
- Year
- 2018
- Shift
- 15 Apr Shift 1 Online
- Q Number
- Q15
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 2: Electrostatic Potential and Capacitance
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