Q44.The gas liberated by the electrolysis of Dipotassium succinate solution is: (1) Ethane (2) Ethyne (3) Ethene (4) Propene
What This Question Tests
This question assesses the understanding of Kolbe's electrolytic method for the synthesis of hydrocarbons, specifically identifying the product (ethane) from the electrolysis of dipotassium succinate.
Concepts Tested
📚 NCERT Sections This Tests
6.21 — Primary Alkyl Halide C4H9Br (A) Reacted With Alcoholic Koh To Give Compound (B).
Chemistry Class 12 · Chapter 6
6.21 Primary alkyl halide C4H9Br (a) reacted with alcoholic KOH to give compound (b). Compound (b) is reacted with HBr to give (c) which is an isomer of (a). When (a) is reacted with sodium metal it gives compound (d), C8H18 which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of (a) and write the equations for all the reactions.
7.18 — Explain The Following With An Example.
Chemistry Class 12 · Chapter 7
7.18 Explain the following with an example. (i) Kolbe’s reaction. (ii) Reimer-Tiemann reaction. (iii) Williamson ether synthesis. (iv) Unsymmetrical ether.
7.7 — Predict The Major Product Of Acid Catalysed Dehydration Of
Chemistry Class 12 · Chapter 7
7.7 Predict the major product of acid catalysed dehydration of (i) 1-methylcyclohexanol and (ii) butan-1-ol
📋 Question Details
- Chapter
- Hydrocarbons
- Topic
- Kolbe's Electrolytic Method
- Year
- 2014
- Shift
- 11 Apr Online
- Q Number
- Q44
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 10: Haloalkanes and Haloarenes (preparation of alkanes from carboxylic acid salts) or Class 11 Chemistry Ch 13: Hydrocarbons
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