Q89.The distance of the point (1, −5, 9) from the plane x −y + z = 5 measured along the line x = y = z is (1) 10 (2) 20 √3 3 (3) 3√10 (4) 10√3
What This Question Tests
This problem involves finding the parametric equation of a line, determining its intersection point with a plane, and then calculating the distance between two points in three-dimensional space.
Concepts Tested
Formulas Used
Parametric equation of a line: x = x₁ + at, y = y₁ + bt, z = z₁ + ct
Distance formula: √((x₂-x₁)²+(y₂-y₁)²+(z₂-z₁)²)
Equation of plane x-y+z=5
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
1.14 — Consider A Uniform Electric Field E = 3 × 103 Î N/C. (A) What Is The
Physics Class 11 · Chapter 1
1.14 Consider a uniform electric field E = 3 × 103 î N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?
5.12 — Write All The Geometrical Isomers Of [Pt(Nh3)(Br)(Cl)(Py)] And How Many Of
Chemistry Class 11 · Chapter 5
5.12 Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
📋 Question Details
- Chapter
- 3D Geometry
- Topic
- Distance of a point from a plane along a line
- Year
- 2016
- Shift
- 03 Apr
- Q Number
- Q89
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 11: Three Dimensional Geometry
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