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MathsMediumNumerical2024 · 27 Jan Shift 1

Q90.A fair die is tossed repeatedly until a six is obtained. Let X denote the number of tosses required and let a = P(X = 3), b = P(X ≥3) and c = P(X ≥6 ∣X > 3). Then b+ca is equal to JEE Main 2024 (27 Jan Shift 1) JEE Main Previous Year Paper

What This Question Tests

This question applies the concept of geometric distribution for the number of trials until the first success. It involves calculating probabilities of specific events and a conditional probability, then combining them according to the given expression.

Concepts Tested

Geometric distributionConditional probabilityIndependent events

Formulas Used

P(X=k) = (1-p)^(k-1) * p

P(X>=k) = (1-p)^(k-1)

P(A|B) = P(A ∩ B) / P(B)

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📋 Question Details

Chapter
Probability
Topic
Geometric Distribution
Year
2024
Shift
27 Jan Shift 1
Q Number
Q90
Type
Numerical
NCERT Ref
Class 12 Mathematics Ch 13: Probability

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