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MathsEasyMCQ2022 · 24 Jun Shift 2

Q80.A random variable X has the following probability distribution: X 0 1 2 3 4 P(X) k 2k 4k 6k 8k The value of P( 1<x<4x≤2 )is equal to (1) 4 (2) 2 7 3 (3) 3 (4) 4 7 5 ¯

What This Question Tests

The question tests the basic understanding of discrete probability distributions and the calculation of conditional probabilities.

Concepts Tested

Probability distributionSum of probabilitiesConditional probability

Formulas Used

Σ P(X=x) = 1

P(A|B) = P(A ∩ B) / P(B)

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📋 Question Details

Chapter
Probability
Topic
Discrete probability distribution and conditional probability
Year
2022
Shift
24 Jun Shift 2
Q Number
Q80
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 13: Probability

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