Q31.In an atom, an electron is moving with a speed of 600 m/s with an accuracy of 0.005%. Certainity with which the position of the electron can be located is (h = 6.6 × 10−34 kg m2 s−1 , mass of electron, em = 9.1 × 10−31 kg ) (1) 1.52 × 10−4 m (2) 5.10 × 10−3 m (3) 1.92 × 10−3 m (4) 3.84 × 10−3 m
What This Question Tests
This question tests the application of Heisenberg's Uncertainty Principle to calculate the minimum uncertainty in position, given the electron's speed and percentage accuracy.
Concepts Tested
Formulas Used
Δx ⋅ mΔv ≥ h / (4π)
Δv = v * (percentage accuracy / 100)
📚 NCERT Sections This Tests
12.6 — (A) Using The Bohr’S Model Calculate The Speed Of The Electron In A
Physics Class 12 · Chapter 12
12.6 (a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels. (b) Calculate the orbital period in each of these levels.
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.3 — A Difference Of 2.3 Ev Separates Two Energy Levels In An Atom. What
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12.3 A difference of 2.3 eV separates two energy levels in an atom. What is the frequency of radiation emitted when the atom make a transition from the upper level to the lower level?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Heisenberg's Uncertainty Principle
- Year
- 2009
- Shift
- Unknown
- Q Number
- Q31
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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