Q32.Ejection of the photoelectron from metal in the photoelectric effect experiment can be stopped by applying 0.5 V when the radiation of 250 nm is used. The work function of the metal is : (1) 4 eV (2) 5.5 eV (3) 4.5 eV (4) 5 eV
What This Question Tests
This question requires applying Einstein's photoelectric equation to calculate the work function using the given stopping potential and incident radiation wavelength.
Concepts Tested
Formulas Used
E = hc/λ
K.E.max = eVs
hν = Φ + K.E.max
📚 NCERT Sections This Tests
11.7 — The Work Function For A Certain Metal Is 4.2 Ev. Will This Metal Give
Physics Class 12 · Chapter 11
11.7 The work function for a certain metal is 4.2 eV. Will this metal give hotoelectric emission for incident radiation of wavelength 330 nm?
11.3 — The Photoelectric Cut-Off Voltage In A Certain Experiment Is 1.5 V.
Physics Class 12 · Chapter 11
11.3 The photoelectric cut-off voltage in a certain experiment is 1.5 V. What is the maximum kinetic energy of photoelectrons emitted?
11.9 — Light Of Wavelength 488 Nm Is Produced By An Argon Laser Which Is
Physics Class 12 · Chapter 11
11.9 Light of wavelength 488 nm is produced by an argon laser which is used in the photoelectric effect. When light from this spectral line is incident on the emitter, the stopping (cut-off) potential of photoelectrons is 0.38 V. Find the work function of the material from which the emitter is made.
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Photoelectric Effect
- Year
- 2018
- Shift
- 15 Apr Shift 1 Online
- Q Number
- Q32
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 2: Structure of Atom
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