Q15.The refractive index of a converging lens is 1. 4. What will be the focal length of this lens if it is placed in a medium of same refractive index ? (Assume the radii of curvature of the faces of lens are R1 and R2 respectively) (1) 1 (2) Infinite (3) R1R2 (4) Zero R1−R2
What This Question Tests
This question tests the understanding of the Lens Maker's formula and how the focal length of a lens changes when the lens is placed in a medium with the same refractive index as the lens material.
Concepts Tested
Formulas Used
1/f = (μ_lens/μ_medium - 1)(1/R₁ - 1/R₂)
📚 NCERT Sections This Tests
9.7 — Double-Convex Lenses Are To Be Manufactured From A Glass Of
Physics Class 12 · Chapter 9
9.7 Double-convex lenses are to be manufactured from a glass of refractive index 1.55, with both faces of the same radius of curvature. What is the radius of curvature required if the focal length is to be 20cm?
9.8 — A Beam Of Light Converges At A Point P. Now A Lens Is Placed In The
Physics Class 12 · Chapter 9
9.8 A beam of light converges at a point P. Now a lens is placed in the path of the convergent beam 12cm from P. At what point does the beam converge if the lens is (a) a convex lens of focal length 20cm, and (b) a concave lens of focal length 16cm?
9.19 — A Screen Is Placed 90Cm From An Object. The Image Of The Object On
Physics Class 12 · Chapter 9
9.19 A screen is placed 90cm from an object. The image of the object on the screen is formed by a convex lens at two different locations separated by 20cm. Determine the focal length of the lens.
📋 Question Details
- Chapter
- Ray Optics
- Topic
- Lens Maker's Formula
- Year
- 2021
- Shift
- 16 Mar Shift 2
- Q Number
- Q15
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 9: Ray Optics and Optical Instruments
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