Q80.Let 𝑋 be a binomially distributed random variable with mean 4 and variance 3. Then 54 𝑃𝑋≤2 is equal to (1) 73 (2) 146 27 27 146 126 (3) (4) 81 81
What This Question Tests
This question tests the understanding of the properties of binomial distribution, specifically calculating n and p from mean and variance, then computing a cumulative probability.
Concepts Tested
Formulas Used
Mean = np
Variance = npq
P(X=k) = nCk p^k q^(n-k)
📚 NCERT Sections This Tests
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📋 Question Details
- Chapter
- Probability
- Topic
- Binomial distribution
- Year
- 2022
- Shift
- 26 Jul Shift 2
- Q Number
- Q80
- Type
- MCQ
- NCERT Ref
- Class 12 Mathematics Ch 13: Probability
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