Q4. Consider a block kept on an inclined plane (inclined at 45° ) as shown in the figure. If the force required to just push it up the incline is 2 times the force required to just prevent it from sliding down, the coefficient of friction between the block and inclined plane (µ) is equal to : . (1) 0. 33 (2) 0. 60 (3) 0. 25 (4) 0. 50
What This Question Tests
This question requires applying the concepts of forces and friction on an inclined plane for both upward and downward motion to determine the coefficient of friction.
Concepts Tested
Formulas Used
F_push_up = mg(sinθ + μcosθ)
F_prevent_down = mg(sinθ - μcosθ)
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📋 Question Details
- Chapter
- Friction
- Topic
- Static Friction on Inclined Plane
- Year
- 2023
- Shift
- 25 Jan Shift 2
- Q Number
- Q4
- Type
- MCQ
- NCERT Ref
- Class 11 Physics Ch 5: Laws of Motion
More from this Chapter
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Q4. A block of weight W rests on a horizontal floor with coefficient of static friction μ. It is desired to make the block move by applying minimum amount of force. The angle θ from the horizontal at which the force should be applied and magnitude of the force F are respectively. μW (1) θ = tan−1(μ), F = F = √1+μ2 μW (2) θ = tan−1 ( μ1 ), √1+μ2 F = 1+μμW (3) θ = 0, F = μW (4) θ = tan−1 ( 1+μμ ),