Q26.In a potentiometer arrangement, a cell of emf 1. 20 V gives a balance point at 36 cm length of wire. This cell is now replaced by another cell of emf 1. 80 V . The difference in balancing length of potentiometer wire in above conditions will be _____ cm.
What This Question Tests
This is a direct application of the potentiometer principle for comparing EMFS, requiring a single formula to find the unknown balancing length.
Concepts Tested
Formulas Used
E1/E2 = L1/L2
📚 NCERT Sections This Tests
3.1 — The Storage Battery Of A Car Has An Emf Of 12 V. If The Internal
Physics Class 11 · Chapter 3
3.1 The storage battery of a car has an emf of 12 V. If the internal resistance of the battery is 0.4 Ω, what is the maximum current that can be drawn from the battery?
3.2 — A Battery Of Emf 10 V And Internal Resistance 3 Ω Is Connected To A
Physics Class 11 · Chapter 3
3.2 A battery of emf 10 V and internal resistance 3 Ω is connected to a resistor. If the current in the circuit is 0.5 A, what is the resistance of the resistor? What is the terminal voltage of the battery when the circuit is closed?
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
📋 Question Details
- Chapter
- Current Electricity
- Topic
- Potentiometer
- Year
- 2022
- Shift
- 25 Jul Shift 2
- Q Number
- Q26
- Type
- Numerical
- NCERT Ref
- Class 12 Physics Ch 3: Current Electricity
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