Q66.If x1, x2, … . . , xn and h11 , h21 , … . . , hn1 are two A.P.s such that x3 = h2 = 8 & x8 = h7 = 20 , then x5 ⋅h10 is equal to (1) 3200 (2) 1600 (3) 2650 (4) 2560
What This Question Tests
This problem involves two arithmetic progressions. Students need to use the given terms to find the common differences and first terms of each AP, then calculate the product of specified terms from each progression.
Concepts Tested
Formulas Used
a_n = a + (n-1)d
📚 NCERT Sections This Tests
2.1 — Two Charges 5 × 10–8 C And –3 × 10–8 C Are Located 16 Cm Apart. At
Physics Class 11 · Chapter 2
2.1 Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
2.2 — A Regular Hexagon Of Side 10 Cm Has A Charge 5 Mc At Each Of Its
Physics Class 11 · Chapter 2
2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
📋 Question Details
- Chapter
- Sequences & Series
- Topic
- Arithmetic Progression
- Year
- 2018
- Shift
- 15 Apr
- Q Number
- Q66
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences and Series
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