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MathsMediumNumerical2023 ยท 06 Apr Shift 1

Q87.Let the tangent to the curve ๐‘ฅ2 + 2๐‘ฅ- 4๐‘ฆ+ 9 = 0 at the point ๐‘ƒ1, 3 on it meet the ๐‘ฆ- axis at ๐ด. Let the line passing through ๐‘ƒ and parallel to the line ๐‘ฅ- 3๐‘ฆ= 6 meet the parabola ๐‘ฆ2 = 4๐‘ฅ at ๐ต. If ๐ต lies on the line 2๐‘ฅ- 3๐‘ฆ= 8, then ๐ด๐ต2 is equal to _______ .

What This Question Tests

This multi-concept question involves finding the tangent to a parabola-like curve, determining coordinates of points based on line equations and parallelism, and finally calculating the square of the distance between two points.

Concepts Tested

Equation of tangent to parabolaEquation of a line parallel to another lineDistance between two points

Formulas Used

Equation of tangent to y^2=4ax at (x1,y1) is yy1=2a(x+x1)

Equation of tangent to x^2=4ay at (x1,y1) is xx1=2a(y+y1)

Distance formula

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