Q62.Let S1 be the sum of first 2n terms of an arithmetic progression. Let S2 be the sum of first 4n terms of the same arithmetic progression. If (S2 −S1) is 1000 , then the sum of the first 6n terms of the arithmetic progression is equal to: (1) 1000 (2) 7000 (3) 5000 (4) 3000
What This Question Tests
This question tests the understanding of the sum of terms in an arithmetic progression and requires setting up equations to solve for the required sum.
Concepts Tested
Formulas Used
S_n = n/2 * [2a + (n-1)d]
📚 NCERT Sections This Tests
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📋 Question Details
- Chapter
- Sequences & Series
- Topic
- Arithmetic Progression
- Year
- 2021
- Shift
- 18 Mar Shift 2
- Q Number
- Q62
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences and Series
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