Q18.The speed of electrons in a scanning electron microscope is 1 × 107 ms−1 . If the protons having the same speed are used instead of electrons, then the resolving power of scanning proton microscope will be changed by a factor of: (1) 1837 (2) 18371 (3) √1837 (4) 1 √1837
What This Question Tests
This question connects the de Broglie wavelength of particles to the resolving power of a microscope and asks for the change in resolving power when electrons are replaced by protons of the same speed.
Concepts Tested
Formulas Used
λ = h/p = h/mv
Resolving Power ∝ 1/λ
📚 NCERT Sections This Tests
11.10 — What Is The De Broglie Wavelength Of
Physics Class 12 · Chapter 11
11.10 What is the de Broglie wavelength of (a) a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s, (b) a ball of mass 0.060 kg moving at a speed of 1.0 m/s, and (c) a dust particle of mass 1.0 × 10–9 kg drifting with a speed of 2.2 m/s ?
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.6 — (A) Using The Bohr’S Model Calculate The Speed Of The Electron In A
Physics Class 12 · Chapter 12
12.6 (a) Using the Bohr’s model calculate the speed of the electron in a hydrogen atom in the n = 1, 2, and 3 levels. (b) Calculate the orbital period in each of these levels.
📋 Question Details
- Chapter
- Dual Nature of Matter
- Topic
- De Broglie wavelength and resolving power
- Year
- 2021
- Shift
- 18 Mar Shift 2
- Q Number
- Q18
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 11: Dual Nature of Radiation and Matter
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