Q53.The sum of number of lone pairs of electrons present on the central atoms of XeO3, XeOF4 and XeF6 is
What This Question Tests
This question assesses the understanding of the hydrogen atomic spectrum and the formula to calculate the maximum number of emission lines when an electron transitions from a higher energy level to the ground state. It is a direct application of a standard formula.
Concepts Tested
Formulas Used
Number of lines = n(n-1)/2 (for transition to ground state)
📚 NCERT Sections This Tests
12.7 — The Radius Of The Innermost Electron Orbit Of A Hydrogen Atom Is
Physics Class 12 · Chapter 12
12.7 The radius of the innermost electron orbit of a hydrogen atom is 5.3×10–11 m. What are the radii of the n = 2 and n =3 orbits?
12.5 — A Hydrogen Atom Initially In The Ground Level Absorbs A Photon,
Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
📋 Question Details
- Chapter
- Atomic Structure
- Topic
- Hydrogen spectrum (Lyman series)
- Year
- 2022
- Shift
- 25 Jul Shift 2
- Q Number
- Q53
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 2: Atomic Structure
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