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PhysicsMediumMCQ2014 · 19 Apr Online

Q16.The electric field in a region of space is given by, E = E0ˆi + 2E0ˆj where E0 = 100 N C−1 . The flux of this field through a circular surface of radius 0. 02 m parallel to the Y ‐Z plane is nearly (1) 0. 02 N m2 C−1 (2) 0. 005 N m2 C−1 (3) 0. 125 N m2 C−1 (4) 3. 14 N m2 C−1

What This Question Tests

This question tests the understanding of electric flux calculation using the dot product of the electric field and the area vector, with correct determination of the area vector's direction.

Concepts Tested

Electric fluxArea vectorDot product

Formulas Used

Φ = E ⋅ A

A = πr²

📚 NCERT Sections This Tests

1.14Consider A Uniform Electric Field E = 3 × 103 Î N/C. (A) What Is The

Physics Class 11 · Chapter 1

84% match

1.14 Consider a uniform electric field E = 3 × 103 î N/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

1.19A Point Charge Causes An Electric Flux Of –1.0 × 103 Nm2/C To Pass

Physics Class 11 · Chapter 1

82% match

1.19 A point charge causes an electric flux of –1.0 × 103 Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface? (b) What is the value of the point charge?

1.18A Point Charge Of 2.0 Mc Is At The Centre Of A Cubic Gaussian

Physics Class 11 · Chapter 1

81% match

1.18 A point charge of 2.0 mC is at the centre of a cubic Gaussian surface 9.0 cm on edge. What is the net electric flux through the surface?