Q39.Anomalous behaviour of oxygen is due to its (1) Large size and high electronegativity (2) Small size and low electronegativity (3) Small size and high electronegativity (4) Large size and low electronegativity
What This Question Tests
This question tests the knowledge of reasons for the anomalous behavior of the first element in a group, specifically oxygen, due to its small size and high electronegativity.
Concepts Tested
📚 NCERT Sections This Tests
4.11 — Explain Giving Reasons:
Chemistry Class 11 · Chapter 4
4.11 Explain giving reasons: (i) Transition metals and many of their compounds show paramagnetic behaviour. (ii) The enthalpies of atomisation of the transition metals are high. (iii) The transition metals generally form coloured compounds. (iv) Transition metals and their many compounds act as good catalyst.
4.13 — How Is The Variability In Oxidation States Of Transition Metals Different From
Chemistry Class 11 · Chapter 4
4.13 How is the variability in oxidation states of transition metals different from that of the non transition metals? Illustrate with examples.
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
📋 Question Details
- Chapter
- p-block Elements
- Topic
- Anomalous Behavior of Elements
- Year
- 2024
- Shift
- 29 Jan Shift 2
- Q Number
- Q39
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 11: The p-Block Elements
More from this Chapter
Q87.Which of the following oxides is amphoteric in character? (1) CaO (2) CO2 (3) SiO2 (4) SnO2
Q77.Which of the following statements is true? (1) H3PO3 is a stronger acid than H2SO3 (2) In aqueous medium HF is a stronger acid than HCl (3) HClO4 is a weaker acid than HClO3 (4) HNO3 is a stronger acid than HNO2
Q94.What products are expected from the disproportionation reaction of hypochlorous acid? (1) HClO3 and Cl2O (2) HClO2 and HClO4 (3) HCl and Cl2O (4) HCl and HClO3
Q45.The stability of dihalides of Si, Ge, Sn and Pb increases steadily in the sequence (1) GeX2 ≪SiX2 ≪SnX2 ≪PbX2 (2) SiX2 ≪GeX2 ≪PbX2 ≪SnX2 (3) SiX2 ≪GeX2 ≪SnX2 ≪PbX2 (4) PbX2 ≪SnX2 ≪GeX2 ≪SiX2