Q60.Which of the following compounds will behave as reducing sugar in an aqueous KOH solution? (1) (2) (3) (4)
What This Question Tests
This question tests the understanding of reducing sugars, which possess a free anomeric carbon capable of existing in open-chain aldehyde or ketone form and thus reacting with mild oxidizing agents like Tollens' reagent in basic solution.
Concepts Tested
📚 NCERT Sections This Tests
6.20 — The Treatment Of Alkyl Chlorides With Aqueous Koh Leads To The Formation Of
Chemistry Class 12 · Chapter 6
6.20 The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
7.17 — Give Equations Of The Following Reactions:
Chemistry Class 12 · Chapter 7
7.17 Give equations of the following reactions: (i) Oxidation of propan-1-ol with alkaline KMnO4 solution. (ii) Bromine in CS2 with phenol. (iii) Dilute HNO3 with phenol. (iv) Treating phenol wih chloroform in presence of aqueous NaOH.
📋 Question Details
- Chapter
- Biomolecules
- Topic
- Reducing sugars
- Year
- 2017
- Shift
- 02 Apr
- Q Number
- Q60
- Type
- MCQ
- NCERT Ref
- Class 12 Chemistry Ch 14: Biomolecules
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