Q51.Among the following species N2, N2+, N2- , N22 - , O2, O2+, O2- , O22 - the number of species showing diamagnetism is
What This Question Tests
This question requires applying Molecular Orbital Theory to determine the electronic configuration, bond order, and magnetic properties (diamagnetic or paramagnetic) for various diatomic and polyatomic species.
Concepts Tested
Formulas Used
MO energy level diagram
Bond order = 1/2 (Nb - Na)
📚 NCERT Sections This Tests
5.15 — Discuss The Nature Of Bonding In The Following Coordination Entities On The
Chemistry Class 11 · Chapter 5
5.15 Discuss the nature of bonding in the following coordination entities on the basis of valence bond theory: (i) [Fe(CN)6] 4– (ii) [FeF6] 3– (iii) [Co(C2O4)3]3– (iv) [CoF6] 3–
5.16 — Draw Figure To Show The Splitting Of D Orbitals In An Octahedral Crystal Field.
Chemistry Class 11 · Chapter 5
5.16 Draw figure to show the splitting of d orbitals in an octahedral crystal field.
5.19 — [Cr(Nh3)6] 3+ Is Paramagnetic While [Ni(Cn)4] 2– Is Diamagnetic. Explain Why?
Chemistry Class 11 · Chapter 5
5.19 [Cr(NH3)6] 3+ is paramagnetic while [Ni(CN)4] 2– is diamagnetic. Explain why? 5.20 A solution of [Ni(H2O)6] 2+ is green but a solution of [Ni(CN)4] 2– is colourless. Explain. 5.21 [Fe(CN)6] 4– and [Fe(H2O)6] 2+ are of different colours in dilute solutions. Why?
📋 Question Details
- Chapter
- Chemical Bonding
- Topic
- Molecular Orbital Theory
- Year
- 2022
- Shift
- 25 Jul Shift 1
- Q Number
- Q51
- Type
- Numerical
- NCERT Ref
- Class 11 Chemistry Ch 4: Chemical Bonding and Molecular Structure
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