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MathsMediumMCQ2021 · 26 Feb Shift 2

Q80.A seven digit number is formed using digits 3, 3, 4, 4, 4, 5, 5 . The probability, that number so formed is divisible by 2 , is (1) 4 (2) 3 7 7 (3) 1 (4) 6 7 7

What This Question Tests

This question involves calculating the probability of a seven-digit number (formed with repeated digits) being divisible by 2, requiring knowledge of permutations with repetition and divisibility rules.

Concepts Tested

Permutation with repetitionDivisibility rulesClassical probability

Formulas Used

n! / (n1! n2! ...)

Favorable outcomes / Total outcomes

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📋 Question Details

Chapter
Probability
Topic
Permutation and Combination
Year
2021
Shift
26 Feb Shift 2
Q Number
Q80
Type
MCQ
NCERT Ref
Class 11 Mathematics Ch 7: Permutations and Combinations, Class 12 Mathematics Ch 13: Probability

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