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MathsMediumMCQ2020 · 07 Jan Shift 1

Q63.Let xk + yk = ak, (a, k > 0) and dx 1 dy + ( xy ) 3 = 0, then k is (1) 3 (2) 4 2 3 (3) 32 (4) 13

What This Question Tests

The problem requires implicitly differentiating the given algebraic relation to find dy/dx and then comparing it with the provided differential equation (after interpreting a likely typo) to determine the value of k.

Concepts Tested

Implicit DifferentiationDifferential EquationsLaws of Exponents

Formulas Used

d(x^n)/dx = nx^(n-1)

d(y^n)/dx = ny^(n-1) dy/dx

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📋 Question Details

Chapter
Differential Equations
Topic
Formation of Differential Equations
Year
2020
Shift
07 Jan Shift 1
Q Number
Q63
Type
MCQ
NCERT Ref
Class 12 Mathematics Ch 5: Continuity and Differentiability; Ch 9: Differential Equations

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