Q15.If ∑nr=1 Tr = (2n−1)(2n+1)(2n+3)(2n+5)64 , then limn→∞∑nr=1 ( Tr1 ) (1) 0 (2) 23 (3) 1 (4) 13
What This Question Tests
This problem requires finding the general term from the given sum of a series, performing partial fraction decomposition, and then evaluating the limit of the sum of reciprocals of the terms.
Concepts Tested
Formulas Used
Tn = Sn - S(n-1) (if sum is given)
Partial fraction decomposition
lim (1/n) = 0 as n->inf
📚 NCERT Sections This Tests
1.3 — Define The Following Terms:
Chemistry Class 11 · Chapter 1
1.3 Define the following terms: (i) Mole fraction (ii) Molality (iii) Molarity (iv) Mass percentage.
8.17 — Complete Each Synthesis By Giving Missing Starting Material, Reagent Or Products
Chemistry Class 12 · Chapter 8
8.17 Complete each synthesis by giving missing starting material, reagent or products
1.27 — If The Solubility Product Of Cus Is 6 × 10–16, Calculate The Maximum Molarity Of
Chemistry Class 11 · Chapter 1
1.27 If the solubility product of CuS is 6 × 10–16, calculate the maximum molarity of CuS in aqueous solution.
📋 Question Details
- Chapter
- Sequences & Series
- Topic
- Partial sums and limits
- Year
- 2025
- Shift
- 22 Jan Shift 1
- Q Number
- Q15
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 9: Sequences & Series; Class 12 Mathematics Ch 13: Limits & Continuity
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