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MathsMediumMCQ2025 · 29 Jan Shift 1

Q2. Consider an A. P. of positive integers, whose sum of the first three terms is 54 and the sum of the first twenty terms lies between 1600 and 1800. Then its 11th term is : (1) 90 (2) 84 (3) 122 (4) 108 − − = 0 is: √x √x

What This Question Tests

The question requires setting up equations based on the sum of the first three terms and an inequality for the sum of the first twenty terms to find the first term and common difference of the AP.

Concepts Tested

Sum of terms in APnth term of APInequalities

Formulas Used

Sn = (n/2)(2a + (n-1)d)

an = a + (n-1)d

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