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PhysicsHardNumerical2020 · 05 Sep Shift 1

Q21.A particle of mass 200 MeV c−2 collides with a hydrogen atom at rest. Soon after the collision, the particle comes to rest, and the atom recoils and goes to its first excited state. The initial kinetic energy of the particle (in eV ) is N4 . The value of N is: (Given the mass of the hydrogen atom to be 1 GeV c−2 )......... → + 2ˆj + m . Then the magnitude of torque about the point N acts at a point (4ˆi + 3ˆj −ˆk)

What This Question Tests

This multi-concept question combines inelastic collision principles with energy conservation, including the internal energy change of a hydrogen atom going to an excited state. It requires careful handling of units.

Concepts Tested

Conservation of momentumConservation of energy (inelastic collision)Hydrogen atom energy levelsRelativistic mass-energy equivalence (for units)

Formulas Used

m₁v₁ = m₂v₂

KE_initial = KE_final + ΔE

E_n = -13.6/n² eV

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