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MathsHardMCQ2017 · 08 Apr Online

Q84.The area (in sq. units) of the smaller portion enclosed between the curves, x2 + y2 = 4 and y2 = 3x, is: (1) √3 1 + 4π3 (2) √31 + 2π3 (3) 2√3 1 + π3 (4) 2√31 + 2π3

What This Question Tests

This question asks for the area of the smaller region enclosed by a circle and a parabola. It requires finding intersection points, splitting the area into parts (one under the parabola, another a circular sector), and calculating both using integration and geometric formulas for area.

Concepts Tested

Intersection points of curvesIntegration with respect to x or yArea of a circle/sector

Formulas Used

Area = ∫ y dx

Area of circular sector = (1/2)r²θ

Area of triangle = (1/2)bh

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