Q30.A charged particle moves through a magnetic field perpendicular to its direction. Then (1) the momentum changes but the kinetic energy is (2) both momentum and kinetic energy of the constant particle are not constant (3) both, momentum and kinetic energy of the (4) kinetic energy changes but the momentum is particle are constant constant
What This Question Tests
This question tests the understanding that magnetic force does no work on a charged particle, thus keeping its kinetic energy constant, but it changes the direction of velocity, thereby changing its momentum.
Concepts Tested
Formulas Used
F = q(v x B)
W = F ⋅ dr
KE = (1/2)mv²
p = mv
📚 NCERT Sections This Tests
4.4 — A Horizontal Overhead Power Line Carries A Current Of 90 A In East To
Physics Class 11 · Chapter 4
4.4 A horizontal overhead power line carries a current of 90 A in east to west direction. What is the magnitude and direction of the magnetic field due to the current 1.5 m below the line?
4.6 — A 3.0 Cm Wire Carrying A Current Of 10 A Is Placed Inside A Solenoid
Physics Class 11 · Chapter 4
4.6 A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?
4.5 — What Is The Magnitude Of Magnetic Force Per Unit Length On A Wire
Physics Class 11 · Chapter 4
4.5 What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?
📋 Question Details
- Chapter
- Magnetic Effects of Current
- Topic
- Force on a charged particle in a magnetic field
- Year
- 2007
- Shift
- Unknown
- Q Number
- Q30
- Type
- MCQ
- NCERT Ref
- Class 12 Physics Ch 4: Magnetic Effects of Current
More from this Chapter
Q49.If a current is passed through a spring then the spring will (1) expand (2) compress (3) insulator (4) none of these
Q52.If in a circular coil A of radius R, current I is flowing and in another coil B of radius 2R a current 2l is flowing, then the ratio of the magnetic fields BA and BB , produced by them will be (1) 1 (2) 2 (3) 1/2 (4) 4
Q53.If an electron and a proton having same momenta enter perpendicular to a magnetic field, then (1) curved path of electron and proton will be same (2) they will move undeflected (ignoring the sense of revolution) (3) curved path of electron is more curved than that (4) path of proton is more curved of the proton
Q54.Wires 1 and 2 carrying currents i1 and i2 respectively are inclined at an angle θ to each other. What is the force on a small element dl of wire 2 at a distance of r from wire 1 (as shown in the figure) due to the magnetic field of wire 1 ? μ0 (1) θ 2πr i1i2dl tan θ (2) 2πrμ0 i1i2 dl sin (3) 2πr μ0 i1i2dl cos θ (4) 4πrμ0 i1i2dl sin θ