Q75. (ΔH −ΔU) for the formation of carbon monoxide (CO) from its elements at 298 K is (R = 8.314 J K−1 mol−1) (1) −1238.78 J mol−1 (2) 1238.78 J mol−1 (3) −2477.57 J mol−1 (4) 2477.57 J mol−1
What This Question Tests
This question tests the ability to apply the relationship between enthalpy change and internal energy change for a reaction involving gases, requiring calculation of change in moles of gas.
Concepts Tested
Formulas Used
ΔH = ΔU + Δn_g RT
📚 NCERT Sections This Tests
3.23 — The Rate Constant For The Decomposition Of Hydrocarbons Is 2.418 × 10–5S–1
Chemistry Class 11 · Chapter 3
3.23 The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor.
12.4 — The Ground State Energy Of Hydrogen Atom Is –13.6 Ev. What Are The
Physics Class 12 · Chapter 12
12.4 The ground state energy of hydrogen atom is –13.6 eV. What are the kinetic and potential energies of the electron in this state?
1.35 — Henry’S Law Constant For The Molality Of Methane In Benzene At 298 K Is
Chemistry Class 11 · Chapter 1
1.35 Henry’s law constant for the molality of methane in benzene at 298 K is 4.27 × 105 mm Hg. Calculate the solubility of methane in benzene at 298 K under 760 mm Hg.
📋 Question Details
- Chapter
- Thermodynamics & Thermochemistry
- Topic
- Enthalpy and internal energy relationship
- Year
- 2006
- Shift
- Unknown
- Q Number
- Q75
- Type
- MCQ
- NCERT Ref
- Class 11 Chemistry Ch 6: Thermodynamics
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