Q68.If the area of the triangle whose one vertex is at the vertex of the parabola, y2 + 4 (x −a2) = 0 and the other two vertices are the points of intersection of the parabola and y -axis, is 250 sq. units, then a value of 'a' is : (1) 5√5 (2) 5 (21/3) (3) (10)33 (4) 5
What This Question Tests
This question requires identifying the vertex of a given parabola, finding its y-intercepts, and then calculating the area of the triangle formed by these three points.
Concepts Tested
Formulas Used
Vertex of y² = -4A(x-h) is (h,0)
Area = 1/2 * base * height
📚 NCERT Sections This Tests
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2.2 A regular hexagon of side 10 cm has a charge 5 mC at each of its vertices. Calculate the potential at the centre of the hexagon.
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Physics Class 12 · Chapter 12
12.5 A hydrogen atom initially in the ground level absorbs a photon, which excites it to the n = 4 level. Determine the wavelength and frequency of photon.
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2.5 A parallel plate capacitor with air between the plates has a capacitance of 8 pF (1pF = 10–12 F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?
📋 Question Details
- Chapter
- Parabola
- Topic
- Properties of parabola and area of triangle
- Year
- 2019
- Shift
- 11 Jan Shift 2
- Q Number
- Q68
- Type
- MCQ
- NCERT Ref
- Class 11 Mathematics Ch 11: Conic Sections
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